mysql取上个月最后一天

获取上个月最后一天

SELECT

date_sub( date_sub( date_format( now(), '%y-%m-%d' ), INTERVAL extract( DAY FROM now()) DAY ), INTERVAL 0 MONTH ) AS date

select

*

from

shipmentlist,shipmentscrib

where

(shipmentlist.shipmentlistno=shipmentscrib.shipmentlistno)

and (year(shipmentlist.shipmentdate)=year(now()))

and (month(shipmentlist.shipmentdate)=month(now())

or month(shipmentlist.shipmentdate)=month(now())-1 )

ORDER BY shipmentdate DESC

格式化了一下你的SQL，分析一下。

假如今天是 2012年1月1日。

那么上面的条件。

将变为

year = 2012 and month = 1 OR month = 0

其实，对于 查询 当月和上一月

相当于

shipmentlist.shipmentdate >= 上月的1号

AND shipmentlist.shipmentdate <下月的1号

LAST_DAY(NOW()) 可以获取 本月的最后一天.

DATE_ADD( LAST_DAY(NOW()) INTERVAL 1 DAY ) 可以获取下月第一天。

DATE_SUB ( DATE_ADD( LAST_DAY(NOW()) INTERVAL 1 DAY ) INTERVAL 2 MONTH ) 可以获取上月的1号

（也就是用 下月的1号 减少2个月，从而获取 上月的1号）

最后 SQL 修改为：

select

*

from

shipmentlist,shipmentscrib

where

(shipmentlist.shipmentlistno=shipmentscrib.shipmentlistno)

and shipmentlist.shipmentdate >= DATE_SUB ( DATE_ADD( LAST_DAY(NOW()) INTERVAL 1 DAY ) INTERVAL 2 MONTH )

AND shipmentlist.shipmentdate <DATE_ADD( LAST_DAY(NOW()) INTERVAL 1 DAY )

ORDER BY shipmentdate DESC

mysql 怎么获取前一个月的日期和前一年的日期

set @dt = now()

select extract(year_month from date_add(@dt, interval -1 month))

select extract(year_month from date_add(@dt, interval -1 year))

这样就可以了

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