ProcessSerialNumber psn = { 0,kCurrentProcess }; (voID) transformProcesstype(&psn,kProcesstransformToForegroundApplication);
然后cocoa应用程序菜单不显示,除非你在应用程序中尽早调用它(例如在applicationWillFinishLaunching中).
解决方法 我向Apple寻求帮助,他们帮助我很好. Quote:The reason why the menu bar isn’t show when you call transformProcesstype is that your app is already the active app (that is,[[NSRunningApplication currentApplication] isActive] returns YES) and the menu bar for an app is shown when the app is activated
这是他们的解决方法:
- (voID)transformStep1 { for (NSRunningApplication * app in [NSRunningApplication runningApplicationsWithBundleIDentifIEr:@"com.apple.finder"]) { [app activateWithOptions:NSApplicationActivateIgnoringOtherApps]; break; } [self performSelector:@selector(transformStep2) withObject:nil afterDelay:0.1];}- (voID)transformStep2{ ProcessSerialNumber psn = { 0,kCurrentProcess }; (voID) transformProcesstype(&psn,kProcesstransformToForegroundApplication); [self performSelector:@selector(transformStep3) withObject:nil afterDelay:0.1];}- (voID)transformStep3{ [[NSRunningApplication currentApplication] activateWithOptions:NSApplicationActivateIgnoringOtherApps];}总结
以上是内存溢出为你收集整理的macos – 调用TransformProcessType()时,应用程序菜单不会显示全部内容,希望文章能够帮你解决macos – 调用TransformProcessType()时,应用程序菜单不会显示所遇到的程序开发问题。
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