用c语言编写程序,用Switch语句编程实现,输入一个正整数,输出该整数除以5的余？

#include<stdio.h>

void main(){

int num

printf("请输入一个正整数：扰迅")

scanf("%d",&num)

while(num<=0){

printf("必须输入一个大于0的正整数!\n\n")

printf("请输入一个正整数：")

scanf("%d",&num)

}

printf("数字%d除以5",num)

switch(num%5){

case 1:

printf("余数是1!")

break

case 2:

printf("缓饥此余数是2!")

break

case 3:

printf("余数是3!")

break

case 4:

printf("余数是4!")

break

default:

printf("肢毕余数是0!")

break

}

printf("\n")

}

#include \x0d\x0aint main( )\x0d\x0a{\x0d\x0a double a, b\x0d\x0a char op\x0d\x0a scanf("%lf%c%lf", &a, &op, &b)\x0d\x0a switch (op)\x0d\x0a {\x0d\x0a case '+':\x0d\x0a printf("%lf + %lf = %lf\n", a, b, a + b)\x0d\x0a break\x0d\x0a case '-':\x0d\x0a printf("%lf - %lf = %lf\n", a, b, a - b)\x0d\x0a break\x0d\x0a case '*':\x0d\x0a printf("%lf * %lf = %lf\n", a, b, a * b)\x0d\x0a break\x0d\x0a case '/':\x0d\x0a if (b != 0)\x0d\x0aprintf("%lf / %lf = %lf\n", a, b, a / b)\x0d\x0a else\x0d\x0a printf("除数不能是0! \n")\x0d\x0a break\x0d\x0a }\x0d\x0a}

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