可以告诉ElementTree保留属性的顺序吗？

可以告诉ElementTree保留属性的顺序吗？

在@bobince的答案和这两个帮助下（设置属性顺序，覆盖模块方法）

我设法修复了这只猴子的脏污，建议使用另一个模块更好地处理这种情况，但是在这种情况下是不可能的：

# =======================================================================# Monkey patch ElementTreeimport xml.etree.ElementTree as ETdef _serialize_xml(write, elem, encoding, qnames, namespaces):    tag = elem.tag    text = elem.text    if tag is ET.Comment:        write("<!--%s-->" % ET._enpre(text, encoding))    elif tag is ET.ProcessingInstruction:        write("<?%s?>" % ET._enpre(text, encoding))    else:        tag = qnames[tag]        if tag is None: if text:     write(ET._escape_cdata(text, encoding)) for e in elem:     _serialize_xml(write, e, encoding, qnames, None)        else: write("<" + tag) items = elem.items() if items or namespaces:     if namespaces:         for v, k in sorted(namespaces.items(),      key=lambda x: x[1]):  # sort on prefix  if k:      k = ":" + k  write(" xmlns%s="%s"" % (      k.enpre(encoding),      ET._escape_attrib(v, encoding)      ))     #for k, v in sorted(items):  # lexical order     for k, v in items: # Monkey patch         if isinstance(k, ET.QName):  k = k.text         if isinstance(v, ET.QName):  v = qnames[v.text]         else:  v = ET._escape_attrib(v, encoding)         write(" %s="%s"" % (qnames[k], v)) if text or len(elem):     write(">")     if text:         write(ET._escape_cdata(text, encoding))     for e in elem:         _serialize_xml(write, e, encoding, qnames, None)     write("</" + tag + ">") else:     write(" />")    if elem.tail:        write(ET._escape_cdata(elem.tail, encoding))ET._serialize_xml = _serialize_xmlfrom collections import OrderedDictclass OrderedXMLTreeBuilder(ET.XMLTreeBuilder):    def _start_list(self, tag, attrib_in):        fixname = self._fixname        tag = fixname(tag)        attrib = OrderedDict()        if attrib_in: for i in range(0, len(attrib_in), 2):     attrib[fixname(attrib_in[i])] = self._fixtext(attrib_in[i+1])        return self._target.start(tag, attrib)# =======================================================================

然后在您的代码中：

tree = ET.parse(pathToFile, OrderedXMLTreeBuilder())