在python中转置嵌​​套列表

在python中转置嵌​​套列表

zip

与

*

和一起使用

map

：

>>> map(list, zip(*a))[['AAA', 'BBB', 'CCC', 'DDD', 'EEE', 'FFF', 'GGG', 'HHH', 'III'], ['1', '262', '86', '48', '8', '39', '170', '16', '4'], ['1', '56', '84', '362', '33', '82', '296', '40', '3'], ['10', '238', '149', '205', '96', '89', '223', '65', '5'], ['92', '142', '30', '237', '336', '140', '210', '50', '2']]

请注意，它会

map

在Python 3中返回一个地图对象，因此您需要

list(map(list, zip(*a)))

使用

list comprehension

with

zip(*...)

，可以像在Python 2和3中一样工作。

[list(x) for x in zip(*a)]

---

NumPy方式：

>>> import numpy as np>>> np.array(a).T.tolist()[['AAA', 'BBB', 'CCC', 'DDD', 'EEE', 'FFF', 'GGG', 'HHH', 'III'], ['1', '262', '86', '48', '8', '39', '170', '16', '4'], ['1', '56', '84', '362', '33', '82', '296', '40', '3'], ['10', '238', '149', '205', '96', '89', '223', '65', '5'], ['92', '142', '30', '237', '336', '140', '210', '50', '2']]