5980. 将字符串拆分为若干长度为 k 的组 - 力扣(LeetCode) (leetcode-cn.com)
解题思路原本以为是几行代码就搞定了,但写起来还是有点复杂,功力还是不够
解题代码import java.util.ArrayList; public class Solution5980 { public String[] divideString(String s, int k, char fill) { int n = s.length(); ArrayList解题结果arrayList = new ArrayList<>(); int i = 0; StringBuilder stringBuilder = new StringBuilder(); while (i < n) { stringBuilder.append(s.charAt(i)); i++; if (i % k == 0) { arrayList.add(stringBuilder.toString()); stringBuilder.delete(0, stringBuilder.length()); } } if (stringBuilder.length() == 0) { return toArray(arrayList); } while (stringBuilder.length() < k) { stringBuilder.append(fill); } arrayList.add(stringBuilder.toString()); return toArray(arrayList); } private String[] toArray(ArrayList arrayList) { String[] strings = new String[arrayList.size()]; for (int k = 0; k < arrayList.size(); k++) { strings[k] = arrayList.get(k); } return strings; } }
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)