扫雷(递归展开)

扫雷(递归展开),第1张

扫雷(递归展开

目的: 通过递归,使其能够展开周围没有雷的格子。

遇到问题:在展开后,如何判断是否赢得游戏。

解决方法:如代码所示。

 


game.h


 

#include
#include
#include

#define ROW 9
#define COL 9
#define ROWS ROW+2
#define COLS COL+2
#define Easy_Count 10

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
void DisplayBoard(char board[ROWS][COLS], int row, int col);
void SetMine(char board[ROWS][COLS], int row, int col);
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

game.c


 

 

#define _CRT_SECURE_NO_WARNINGS

#include"game.h"

int success(char show[ROWS][COLS])
{	
	int i = 1;
	int j = 1;
	int win = 0;
	for (i = 1; i <10; i++)
	{
		for (j = 1; j <10; j++)
		{
			if (show[i][j] =='*')
			{
				win++;
				
			}
		}
	}
	return win;
}
int get_mine_count(char mine[ROWS][COLS], int x, int y)
{
	return mine[x - 1][y] + mine[x - 1][y - 1] + mine[x - 1][y + 1] +
		mine[x][y - 1] + mine[x][y + 1] + mine[x + 1][y] + mine[x + 1][y - 1] + mine[x + 1][y + 1]
		- 8 * '0';
}

void Open(char mine[ROWS][COLS], char show[ROWS][COLS], int x, int y)
{
	int count = get_mine_count(mine, x, y);
	if (count==0)
	{
		show[x][y] = ' ';
		int i = 0;
		int j = 0;
		for (i = x - 1; i <= x + 1; i++)
		{
			for (j = y - 1; j <= y + 1; j++)
			{
				if (show[i][j] == '*' && i > 0 && i < 10 && j > 0 && j < 10)
					Open(mine, show, i, j);
			}
		}
	}
	else
	{
		show[x][y] = count + '0';
		
	}
}




void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
	int i = 0;
	int j = 0;
	for (i = 0; i < rows; i++)
	{
		for (j = 0; j < cols; j++)
		{
			board[i][j] = set;
		}
	}
}
void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
	int i = 0;
	int j = 0;
	for (i = 0; i <= row; i++)
	{
		printf("%d ", i);
	}
	printf("n");
	for (i = 1; i <= row; i++)
	{
		printf("%d ", i);
		for (j = 1; j <= col; j++)
		{
			printf("%c ", board[i][j]);
		}
		printf("n");
	}
}
void SetMine(char board[ROWS][COLS], int row, int col)
{
	int count = Easy_Count;
	while (count)
	{
		int x = rand() % row + 1;
		int y = rand() % col + 1;
		if (board[x][y] == '0')
		{
			board[x][y] = '1';
			count--;
		}
	}
}
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	while (win < Easy_Count+1)
	{
		printf("请输入要排查的坐标:>");
		
		
		
		
		scanf("%d%d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (mine[x][y] == '1')
			{
				printf("你被炸死了n");
				DisplayBoard(mine, ROW, COL);
				break;
			}
			else if (show[x][y] != '*')
			{
				printf("选择重复,请重选n");
			}
			else
			{
				Open(mine, show, x, y);
				DisplayBoard(show, ROW, COL);
			}
		}
		else
		{
			printf("输入非法坐标,请重新输入n");

		}
		
		if (success(show) == Easy_Count)
		{
			printf("你赢了n");
			break;
		}
	}
	
}

test.c


 

 

#define _CRT_SECURE_NO_WARNINGS

#include"game.h"

void menu()
{
	printf("**********************n");
	printf("******  1.play   *****n");
	printf("******  0.exit   *****n");
	printf("**********************n");
}

void game()
{
	char mine[ROWS][COLS] = { 0 };
	char show[ROWS][COLS] = { 0 };
	InitBoard(mine, ROWS, COLS, '0');
	InitBoard(show, ROWS, COLS, '*');
	//DisplayBoard(mine, ROW, COL);
	DisplayBoard(show, ROW, COL);
	SetMine(mine, ROW, COL);
	DisplayBoard(mine, ROW, COL);
	FindMine(mine, show, ROW, COL);
}

void test()
{
	int input = 0;
	do
	{

		menu();
		printf("请选择:>");
		scanf("%d", &input);
		switch (input)
		{
		case 1:
			game();
			break;
		case 0:
			printf("退出游戏n");
			break;
		default:
			printf("选择错误,请重新输入n");
			break;
		}
	} while (input);
}

int main()
{
	srand((unsigned int)time(NULL));
	test();
	return 0;
}

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原文地址: https://outofmemory.cn/zaji/5714893.html

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