Myeclipse8.5的web项目中怎么导入struts标签啊

Myeclipse8.5的web项目中怎么导入struts标签啊,第1张

1、右键工程文件夹;

2、在菜单中选择MyEclipse;

3、点击Add Struts Capabilities;

4、选择相应的Struts版本,推荐2.1,下一步

5、完成.

一、需要导入的包:

commons-logging-1.0.4.jar

freemarker-2.3.8.jar

ognl-2.6.11.jar

struts2-core-2.0.11.jar

xwork-2.0.4.jar

二、配置文件

1。web.xml:

<?xml version="1.0" encoding="UTF-8"?>

<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"

xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee

http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

<display-name>Struts 2.0 Hello World</display-name>

<filter>

<filter-name>struts2</filter-name>

<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>

</filter>

<filter-mapping>

<filter-name>struts2</filter-name>

<url-pattern>/*</url-pattern>

</filter-mapping>

</web-app>

2。struts.xml:

<!DOCTYPE struts PUBLIC

"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"

"http://struts.apache.org/dtds/struts-2.0.dtd">

<struts>

<include file="struts-default.xml"/>

<package extends="struts-default">

<action >

<result >/success.jsp</result>

<result >/error.jsp</result>

<result type="redirect">Login!error.action?key=${}</result>

</action>

</package>

</struts>

注:<result type="redirect">Login!error.action?key=${}</result>

其中type="redirect"指的是可以按url重定向,其中当然可以写入带参数的URL了。

key必须在action中定义变量,${}是传参数的格式,可以写入变量的名字也可不写。

3。struts.properties

struts.devMode=true

struts.enable.DynamicMethodInvocation=true //允许使用动态方法

struts.custom.i18n.resources=label

4。Login.java

package com.pac.struts2

import javax.servlet.http.HttpServletRequest

import org.apache.struts2.ServletActionContext

import com.opensymphony.xwork2.ActionSupport

public class Login extends ActionSupport{

private String message

private String userName

private String key

public String getMessage() {

return message

}

public void setMessage(String message) {

this.message = message

}

public String getUserName() {

return userName

}

public void setUserName(String userName) {

this.userName = userName

}

public String getKey() {

return key

}

public void setKey(String key) {

this.key = key

}

public String login(){

String message1 = " Hello, 请填写用户名!"

HttpServletRequest request = ServletActionContext.getRequest()

if(getUserName()==null || "".equals(getUserName())){

return LOGIN

}

message = getUserName()+"你好啊!!"

return SUCCESS

}

public String error() throws Exception {

HttpServletRequest request = ServletActionContext.getRequest()

String key = request.getParameter("key")

if(key!=null &&!"".equals(key)){

setKey(key+" 你好啊!!")

}else{

setKey("mmm 你好啊!!")

}

message = getKey()

return SUCCESS

}

}

5。页面

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>

<%@ taglib prefix = "s" uri = "/struts-tags" %>

<%

String path = request.getContextPath()

String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/"

%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<html>

<head>

<base href="<%=basePath%>">

<title>My JSP 'success.jsp' starting page</title>

<meta http-equiv="pragma" content="no-cache">

<meta http-equiv="cache-control" content="no-cache">

<meta http-equiv="expires" content="0">

<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">

<meta http-equiv="description" content="This is my page">

<!--

<link rel="stylesheet" type="text/css" href="styles.css">

-->

</head>

<body>

<font color="green">This is my success page.</font><br>

<s:property value="message"/>

</body>

</html>

为什么把struts2的配置文件,引入web.xml呢

<!-- 定义Struts2的FilterDispatcher的Filter -->

<filter>

<!-- 定义核心Filter的名字 -->

<filter-name>struts2</filter-name>

<!-- 定义核心Filter的实现类 -->

<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>

</filter>

<!-- FilterDispatcher用来初始化Struts2并且处理所有的Web请求 -->

<filter-mapping>

<filter-name>struts2</filter-name>

<url-pattern>*.do</url-pattern>

</filter-mapping>

这样写不就行了吗?


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