public void destroy() {
}
public void doFilter(ServletRequest arg0, ServletResponse arg1,
FilterChain arg2) throws IOException, ServletException {
HttpServletRequest req=(HttpServletRequest)arg0
String ip=req.getRemoteAddr()
if("192.168.70.88".equals(ip)){
req.getRequestDispatcher("error.jsp")
//arg2.doFilter(arg0, arg1)
}
req.getRequestDispatcher("success.jsp")
}
public void init(FilterConfig arg0) throws ServletException {
}
}
按我给你发的消息弄的话,下面的就不用了你new个servlet虽然也是.java,但它是给你写好基本的doget,dopost还有前边的一堆,省的你手写了,你建完先不忙编代码,把下面的弄了,访问下试试,还不行的话给我发消息。
web.xml里添加如下:(假设你建的servlet在com.xxx包下)
<servlet>
<servlet-name>TimeServlet</servlet-name>
<servlet-class>这写完整路径,比如com.xxx.TimeServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>TimeServlet</servlet-name>
<url-pattern>/TimeServlet</url-pattern>
</servlet-mapping>
然后用你那个地址访问就对了
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