python学习笔记-函数

概述函数：传递列表传递函数defshow_magicians(magician_names):formagician_nameinmagician_names:print(magician_name.title())magician_names=['tom','hanan','jay']show_magicians(magician_names)在函数中修改列表将列表传递给函数后 函数：传递列表传递函数

def show_magicians(magician_names):    for magician_name in magician_names:        print(magician_name.Title())        magician_names = ['tom','hanan','jay']show_magicians(magician_names)

在函数中修改列表

将列表传递给函数后，函数就可对其进行修改。在函数中对列表的修改都是永久性的。

def show_magicians(magician_names):    for magician_name in magician_names:        print(magician_name.Title())def make_great(magician_names, new_magician_names):    while magician_names:        current_name = 'the Great ' + magician_names.pop()        new_magician_names.append(current_name)    magician_names = ['tom','hanan','jay']new_magician_names = []make_great(magician_names, new_magician_names)show_magicians(new_magician_names)

禁止函数修改列表

由于在函数中修改列表是永久性的，因此需要使用切片表示法创建列表的副本，对其副本进行修改，从而保留原始列表

'''定义一个函数，打印列表中所有的元素'''def show_magicians(magician_names):    for magician_name in magician_names:        print(magician_name.Title())'''修改列表中的元素'''def make_great(magician_names, new_magician_names):    while magician_names:        current_name = 'the Great ' + magician_names.pop()        new_magician_names.append(current_name)    magician_names = ['tom','hanan','jay']new_magician_names = []make_great(magician_names[:], new_magician_names)show_magicians(magician_names)show_magicians(new_magician_names)

调用函数时，对需要保留的原始列表做相应的处理。

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