python–zipfile提取时的unicode错误

概述我有一个小脚本,它将提取.zip文件.这很好用,但仅适用于.zip文件,它们的文件名中不包含带有“ä”,“ö”,“ü”(等等)字母的文件.否则我收到此错误：Exception in thread Thread-1: Traceback (most recent call last): File 'threading.pyc', line 552, in

我有一个小脚本,它将提取.zip文件.
这很好用,但仅适用于.zip文件,它们的文件名中不包含带有“ä”,“ö”,“ü”(等等)字母的文件.
否则我收到此错误：

Exception in thread Thread-1:Traceback (most recent call last):  file "threading.pyc",line 552,in __bootstrap_inner  file "install.py",line 92,in run  file "zipfile.pyc",line 962,in extractall  file "zipfile.pyc",line 950,in extract  file "zipfile.pyc",line 979,in _extract_member  file "ntpath.pyc",line 108,in joinUnicodeDecodeError: 'ascii' codec can't decode byte 0x94 in position 32: ordinal not in range(128)

这是我的脚本的提取部分：

zip = zipfile.Zipfile(path1)zip.extractall(path2)

我怎么解决这个问题？最佳答案一个建议：

我这样做时收到错误：

>>> c = chr(129)>>> c + u'2'Traceback (most recent call last):  file "

有一个unicode字符串传递到某处加入.

可能是zipfile的文件路径是用unicode编码的吗？
如果你这样做怎么办：

zip = zipfile.Zipfile(str(path1))zip.extractall(str(path2))

或这个：

zip = zipfile.Zipfile(unicode(path1))zip.extractall(unicode(path2))

这是ntpath中的第128行：

def join(a,*p): # 63    for b in p: # 68                path += "\" + b  # 128

第二个建议：

from ntpath import *def join(a,*p):    """Join two or more pathname components,inserting "\" as needed.    If any component is an absolute path,all prevIoUs path components    will be discarded."""    path = a    for b in p:        b_wins = 0  # set to 1 iff b makes path irrelevant        if path == "":            b_wins = 1        elif isabs(b):            # This probably wipes out path so far.  However,it's more            # complicated if path begins with a drive letter:            #     1. join('c:','/a') == 'c:/a'            #     2. join('c:/','/a') == 'c:/a'            # But            #     3. join('c:/a','/b') == '/b'            #     4. join('c:','d:/') = 'd:/'            #     5. join('c:/','d:/') = 'd:/'            if path[1:2] != ":" or b[1:2] == ":":                # Path doesn't start with a drive letter,or cases 4 and 5.                b_wins = 1            # Else path has a drive letter,and b doesn't but is absolute.            elif len(path) > 3 or (len(path) == 3 and                                   path[-1] not in "/\"):                # case 3                b_wins = 1        if b_wins:            path = b        else:            # Join,and ensure there's a separator.            assert len(path) > 0            if path[-1] in "/\":                if b and b[0] in "/\":                    path += b[1:]                else:                    path += b            elif path[-1] == ":":                path += b            elif b:                if b[0] in "/\":                    path += b                else:                    # !!! modify the next line so it works !!!                    path += "\" + b            else:                # path is not empty and does not end with a backslash,# but b is empty; since,e.g.,split('a/') produces                # ('a',''),it's best if join() adds a backslash in                # this case.                path += '\'    return pathimport ntpathntpath.join = join

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