Kotlin list在遍历时删除元素方法汇总

方法一：Iterator迭代器

val list = arrayListOf("1", "2", "3", "4", "5", "6")

val iterator = list.iterator()
while (iterator.hasNext()){
    if (iterator.next() == "4"){
        iterator.remove()
    }
}
        
println("result: $list")  //result: [1, 2, 3, 5, 6]

方法二：for循环

val list = arrayListOf("1", "2", "3", "4", "5", "6")

for (index in list.size - 1 downTo 0){
    if (list[index] == "3") {
        list.removeAt(index)
    }
}

println("result: $list") //result: [1, 2, 4, 5, 6]

方法三：removeIf

val list = arrayListOf("1", "2", "3", "4", "5", "6")

//minSdkVersion >= 24(N)
list.removeIf {
    it == "5"
}

println("result: $list") //result: [1, 2, 3, 4, 6]

方法四：removeAll + filter

val list = arrayListOf("1", "2", "3", "4", "5", "6")

list.removeAll(list.filter {
    it == "2"
})

println("result: $list") //result: [1, 3, 4, 5, 6]