c#中如何改变控件位置.?

利用鼠标事件控制位置，比如：

private void butPlan_MouseMove(object sender, MouseEventArgs e)

{

//播放歌曲快进

if (e.Button == MouseButtons.Left && butPlay.BackgroundImage == FFS)

{

timer2.Enabled = false

butPlan.Location = new Point(MousePosition.X - this.Location.X-10, prTime.Location.Y)

if ( butPlan .Location.X <2 )

{

butPlan.Location = new Point(prTime.Location.X, prTime.Location.Y)

}

if (butPlan.Location.X > prTime.Size.Width -4)

{

butPlan.Location = new Point(prTime.Location.X + prTime.Size.Width - 4, prTime.Location.Y)

}

prTime.Value = (MousePosition.X - this.Location.X-3) * (prTime.Maximum / prTime.Size.Width)-6000

TT((prTime.Value/1000).ToString ())

}

}

private void butPlan_MouseCaptureChanged(object sender, EventArgs e)

{

try

{

timer2.Enabled = true

Music.CurrentPosition = prTime.Value / 1000

MusicLrc.Text = ""

}

catch { }

}

每个控件都有一个Anchor属性，他可以分别锁定控件与窗体Top, Bottom, Left, Right边的距离，效果你自己试试。

还有一种方法可以自己写，在窗体的SizeChanged事件中求得窗体size（即 Height，Width属性）变化前后的比例，然后再按照这个比例改变控件的Location就可以了。 你想要什么样的效果用这个方法，我想都行吧，可以找我。

我是新手只想到这个了，嘿嘿，有高手解答的话，我正好的学习..

控制控件的Location属性啊.

比如有个固定的textBox1

TextBox dynTextBox1 = new TextBox()

dynTextBox1.Location = new Point(textBox1.Location.X,textBox1.Location.Y+15)//X坐标不变,Y坐标加15

TextBox dynTextBox2 = new TextBox()

dynTextBox2.Location = new Point(dynTextBox1.Location.X,dynTextBox1.Location.Y+15))//X坐标不变,Y坐标加15

this.panel1.Controls.Add(dynTextBox1)

this.panel1.Controls.Add(dynTextBox2)

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