Oracle查询一段日期内的星期的日期..例如我要查2011-3-18至2011-3-30内所有星期一的日期..应该怎样查询

select tdate, to_char(tdate,'day')

from (

select to_date('2011-03-18','yyyy-mm-dd') + rownum -1 as tdate

from all_objects

where rownum <= to_date('2011-03-30','yyyy-mm-dd') - to_date('2011-03-18','yyyy-mm-dd') + 1

) t

where to_char(tdate,'day') = '星期一'

其中t表是构建你需要的这一个时间段的日期列表, to_char(days,'day')得到的结果是星期几

select

from (select to_date('2013-01-01', 'yyyy-mm-dd') + rownum - 1 days

from dba_objects) a

where extract(year from days) = 2013

and to_char(days, 'WW') = 22

and to_char(days, 'day') in ('星期一', '星期二', '星期三', '星期四', '星期五')

年份：2013，第几周：22

SELECT to_char(SYSDATE,'iw') -to_char(last_day(add_months( SYSDATE,-1))+1,'iw')+1 FROM DUAL;

这样统计出来的每月的1号所在的周为第一周

select SUNDAY,SATURDAY from

(select

sundaythe_week,decode(sign(sundaythe_day-saturdaythe_day),-1,sundaythe_day,sundaythe_day-7)

sunday,saturdaythe_day saturday from

(select to_char(wwm,'WW') the_week,to_char(wwm,'D') the_daynum,wwm the_day from (select

trunc(sysdate, 'MM')+rownum-1 as wwm from user_objects where rownum < 366) where

to_char(wwm,'D')=1 ) sunday,

(select to_char(wwm,'WW') the_week,to_char(wwm,'D') the_daynum,wwm the_day from (select

trunc(sysdate, 'MM')+rownum-1 as wwm from user_objects where rownum < 366) where

to_char(wwm,'D')=7 ) saturday

where sundaythe_week=saturdaythe_week) a

where the_week=32

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