求编一个统计程序？

jg=0:zh=0:li=0:yx=0:mf=0:bjg=0

do

a= inputbox("输入分数！"&vbcr&"输入-1结束分数输入！")

if a="-1" then

exit do

end if

if a <>"" then

Select Case int(a)\10

Case "0"bjg=bjg+1

Case "1"bjg=bjg+1

Case "2"bjg=bjg+1

Case "3"bjg=bjg+1

Case "4"bjg=bjg+1

Case "5"bjg=bjg+1

Case "6"jg=jg+1

Case "7"zh=zh+1

Case "8"li=li+1

Case "9"yx=yx+1

Case "10" mf=mf+1

Case Else msgbox "无效成绩！"

End Select

end if

loop

str = "59分以下："&bjg&"个"&vbcr

str = str&" 60-69分："&jg&"个"&vbcr

str = str&" 70-79分："&zh&"个"&vbcr

str = str&" 80-89分："&li&"个"&vbcr

str = str&" 90-99分："&yx&"个"&vbcr

str = str&" 100分："&mf&"个"

msgbox str,,"成绩统计！"

#include <stdio.h>

void main()

{

int i, n, renofloat score[30], avr, a, b, c

char name[30][9]

for(i = 0i <30i++)

{

printf("%d号的成绩：", i+1)scanf("%f", &score[i])

if(score[i] <0) break

printf("%d号的姓名：", i+1)scanf("%s", name[i])

}

n = i

printf("统计不及格人数:\n")

reno = 0avr = 0

for(i = 0i <ni++)

{

if( score[i] <60) { reno++printf("%d, %s\n", i+1, name[i])}

avr += score[i]

}

printf("不及格人数为%d\n\n", reno)

printf("统计成绩在平均分及平均分之上的学生人数:\n")

avr /= nreno = 0

for(i = 0i <ni++)

{

if(score[i] >= avr) { reno++printf("%d, %s\n", i+1, name[i])}

}

printf("成绩在平均分及平均分之上的学生人数为%d\n\n", reno)

printf("统计各分数段的人数及所占百分比（分数段为<60,60~79,>=80）:\n")

a = b = c =0

for(i = 0i <ni++)

{

if(score[i] <60) a++

else if(score[i] >= 80) c++

else b++

}

printf("<60:\t%.1f%%\n60~79:\t%.1f%%\n>=80:\t%.1f%%\n",100*a/n,100*b/n,100*c/n)

}

#include <stdio.h>

int main()

{

float x[8]={9.2,9.5,9.0,8.9,9.3,9.5,9.1,9.0}

float max, min

int i

float avg = 0

max = min = x[0]

for (i = 0i <8i++)

{

if (x[i] >max)

{

max = x[i]

}

if (x[i] <min)

{

min = x[i]

}

avg += x[i]

}

avg = (avg - max - min) / 6

printf("the avrage sorce is: %f.\n", avg)

return 0

}

---