Linux利用while实现直角三角形的输出

for((i=$1i>0i--))

do

for((j=1j<=ij++))

do

echo -n "* "

done

echo

done

输出结果

* * * * *

* * * *

* * *

* *

*

read -p "please input the longs:" long

for((i=1i<=$longi++))

do

for((j=$longj>ij--))

do

echo -n " "

done

for m in `seq 1 $i`

do

echo -n "+"

done

for((n=1n<in++))

do

echo -n "+"

done

echo ""

done

long为你自己输入的边长，如果有规定长度，把$long改成数就行