JQuery ajax调用的返回值

不幸的是，您不能将值返回给包装异步回调的函数。取而代之的是，您从AJAX请求进行的成功回调会将数据和控制权移交给另一个函数。我在下面演示了这个概念：

myFunction的定义：

// I added a second parameter called "callback", which takes a function // as a first class objectfunction myFunction(data, callback) {    var result = false;    $.ajax({        type: "POST",        contentType: "application/json",        dataType: "json",        url: "url",        data: data,        error: function(data){ result = false; // invoke the callback function here if(callback != null)  {     callback(result); } // this would return to the error handler, which does nothing //return false;        },        success: function(data){ result = true; // invoke your callback function here if(callback != null) {     callback(result);      } // this would actually return to the success handler, which does   // nothing as it doesn't assign the value to anything // return true;        }     });     // return result; // result would be false here still}

回调函数定义：

// this is the definition for the function that takes the data from your // AJAX success handlerfunction processData(result) {    // do stuff with the result here}

调用myFunction：

var data = { key: "value" }; // pass in both the data as well as the processData function object // in Javascript, functions can be passed into parameters as arguments!myFunction(data, processData);