#include
int main()
{
int a,b,n;
double m,i,sum;
a = 0;b = 1;
m = 1.0;i = 1.0;sum = 0.0;
scanf("%d",&n);
while(a < n)
{
sum += m;
a++;
b = -b;
i++;
m = b/i;
}
printf("%5.2f\n",sum);
return 0;
}
希望大家提出好的建议,感谢!
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)