android – 用于json对象的Volley Post方法

概述data={ "request": { "type": "event_and_offer", "devicetype": "A" }, "requestinfo": { "value": "offer" }} 如何从volley plz帮助发布此请求 JsonObjectRequest jsonObjReq = new

data={    "request": {       "type": "event_and_offer","devicetype": "A"    },"requestinfo": {       "value": "offer"      }}

如何从volley plz帮助发布此请求

JsonObjectRequest JsonObjReq = new JsonObjectRequest(            Request.Method.POST,url,null,new Response.Listener<JsONObject>() {                @OverrIDe                public voID onResponse(JsONObject response) {                    Log.d(TAG,response.toString());                    msgResponse.setText(response.toString());                    hIDeProgressDialog();                }            },new Response.ErrorListener() {                @OverrIDe                public voID onErrorResponse(VolleyError error) {                    VolleyLog.d(TAG,"Error: " + error.getMessage());                    hIDeProgressDialog();                }            }) {        /**         * Passing some request headers         * */        @OverrIDe        public Map<String,String> getheaders() throws AuthFailureError {            HashMap<String,String> headers = new HashMap<String,String>();            headers.put("Content-Type","application/x-www-form-urlencoded");            return headers;        }

Js是我的Jsson对象……我让我的Jsson像这样……

JsONObject Jsonobject_one = new JsONObject();    try {        Jsonobject_one.put("type","event_and_offer");        Jsonobject_one.put("devicetype","I");        JsONObject Jsonobject_TWO = new JsONObject();        Jsonobject_TWO.put("value","event");        Jsonobject = new JsONObject();        Jsonobject.put("requestinfo",Jsonobject_TWO);        Jsonobject.put("request",Jsonobject_one);        Js = new JsONObject();        Js.put("data",Jsonobject.toString());        Log.e("created Jsson","" + Js);

但它没有回应plzz帮助的价值

解决方法 首先你的Json数据：

JsONObject Js = new JsONObject();try {    JsONObject Jsonobject_one = new JsONObject();    Jsonobject_one.put("type","event_and_offer");    Jsonobject_one.put("devicetype","I");    JsONObject Jsonobject_TWO = new JsONObject();    Jsonobject_TWO.put("value","event");    JsONObject Jsonobject = new JsONObject();    Jsonobject.put("requestinfo",Jsonobject_TWO);    Jsonobject.put("request",Jsonobject_one);    Js.put("data",Jsonobject.toString());}catch (JsONException e) {        e.printstacktrace();}

然后你的Json请求：

JsonObjectRequest JsonObjReq = new JsonObjectRequest(        Request.Method.POST,Js,new Response.Listener<JsONObject>() {            @OverrIDe            public voID onResponse(JsONObject response) {                Log.d(TAG,response.toString());                msgResponse.setText(response.toString());                hIDeProgressDialog();            }        },new Response.ErrorListener() {            @OverrIDe            public voID onErrorResponse(VolleyError error) {                VolleyLog.d(TAG,"Error: " + error.getMessage());                hIDeProgressDialog();            }        }) {    /**     * Passing some request headers     * */    @OverrIDe    public Map<String,String> getheaders() throws AuthFailureError {         HashMap<String,String>();         headers.put("Content-Type","application/Json; charset=utf-8");        return headers;    }

注意标题

如果你想在localhost中测试使用下面的代码并设置你的url连接你的localhost服务器和IP地址：
下面的代码将您的所有请求放在一个文本文件中,我尝试了它,它的工作原理

<?PHPfile_put_contents('test.txt',file_get_contents('PHP://input'));?>

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