逆程序授信是什么意思

指违反规定逆程序或者减程序办理授信业务。授信发放是指授信业务经审批同意后到授信对象实际使用银行信用之前的各个环节的管理过程，包括落实授信条件、放款审核及档案管理等环节。逆程序授信属于违法行为，会受到法律的严惩。

算法没有问题，只是

for(i=0i<n-1i++)

{

for(int

j=0j<n-i-1j++)

{

temp=a[j+1]

a[j+1]=a[j]

a[j]=temp

}

}

去掉for循环之后的分号就好了

分号放在for循环之后，循环就只执行一次了～

#include <stdlib.h>

#include <math.h>

#include <stdio.h>

int brinv(double a[], int n)

{ int *is,*js,i,j,k,l,u,v

double d,p

is=malloc(n*sizeof(int))

js=malloc(n*sizeof(int))

for (k=0k<=n-1k++)

{ d=0.0

for (i=ki<=n-1i++)

for (j=kj<=n-1j++)

{ l=i*n+jp=fabs(a[l])

if (p>d) { d=pis[k]=ijs[k]=j}

}

if (d+1.0==1.0)

{ free(is)free(js)printf("err**not inv\n")

return(0)

}

if (is[k]!=k)

for (j=0j<=n-1j++)

{ u=k*n+jv=is[k]*n+j

p=a[u]a[u]=a[v]a[v]=p

}

if (js[k]!=k)

for (i=0i<=n-1i++)

{ u=i*n+kv=i*n+js[k]

p=a[u]a[u]=a[v]a[v]=p

}

l=k*n+k

a[l]=1.0/a[l]

for (j=0j<=n-1j++)

if (j!=k)

{ u=k*n+ja[u]=a[u]*a[l]}

for (i=0i<=n-1i++)

if (i!=k)

for (j=0j<=n-1j++)

if (j!=k)

{ u=i*n+j

a[u]=a[u]-a[i*n+k]*a[k*n+j]

}

for (i=0i<=n-1i++)

if (i!=k)

{ u=i*n+ka[u]=-a[u]*a[l]}

}

for (k=n-1k>=0k--)

{ if (js[k]!=k)

for (j=0j<=n-1j++)

{ u=k*n+jv=js[k]*n+j

p=a[u]a[u]=a[v]a[v]=p

}

if (is[k]!=k)

for (i=0i<=n-1i++)

{ u=i*n+kv=i*n+is[k]

p=a[u]a[u]=a[v]a[v]=p

}

}

free(is)free(js)

return(1)

}

void brmul(double a[], double b[],int m,int n,int k,double c[])

{ int i,j,l,u

for (i=0i<=m-1i++)

for (j=0j<=k-1j++)

{ u=i*k+jc[u]=0.0

for (l=0l<=n-1l++)

c[u]=c[u]+a[i*n+l]*b[l*k+j]

}

return

}

int main()

{ int i,j

static double a[4][4]={ {0.2368,0.2471,0.2568,1.2671},

{1.1161,0.1254,0.1397,0.1490},

{0.1582,1.1675,0.1768,0.1871},

{0.1968,0.2071,1.2168,0.2271}}

static double b[4][4],c[4][4]

for (i=0i<=3i++)

for (j=0j<=3j++)

b[i][j]=a[i][j]

i=brinv(a,4)

if (i!=0)

{ printf("MAT A IS:\n")

for (i=0i<=3i++)

{ for (j=0j<=3j++)

printf("%13.7e ",b[i][j])

printf("\n")

}

printf("\n")

printf("MAT A- IS:\n")

for (i=0i<=3i++)

{ for (j=0j<=3j++)

printf("%13.7e ",a[i][j])

printf("\n")

}

printf("\n")

printf("MAT AA- IS:\n")

brmul(b,a,4,4,4,c)

for (i=0i<=3i++)

{ for (j=0j<=3j++)

printf("%13.7e ",c[i][j])

printf("\n")

}

}

}

这个行么？不知道是不是你要的，希望对你有用

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