在主程序中创建类location的两个对象A和B，A的坐标点应该在何处？

主程序中创建类location的两个对象A和B，A的坐标点设置方式如下：

类Location的参考框架如下：

class Location

{public:

\x05 Location(double,double)//构造函数

\x05 double getx()//成员函数,取x坐标值

\x05 double gety()//成员函数,取y坐标值

double distance(Location &)//成员函数,求给定两点之间的距离

friend double distance(Location &,Location &)//友元函数,求给定两点之间的距离

private:

\x05 double x,y

}

坐标设置如下：

#include

#include

class Location

{

public:

\x05Location(double,double)//构造函数

\x05double getx()//成员函数,取x坐标值

\x05double gety()//成员函数,取y坐标值

\x05double distance(Location &)//成员函数,求给定两点之间的距离

\x05friend double distance(Location &,Location &)//友元函数,求给定两点之间的距离

private:

\x05double x,y

}

Location::Location(double x,double y)

{

\x05this->x = x

\x05this->y = y

}

double Location::getx()

{

\x05return this->x

}

double Location::gety()

{

\x05return this->y

}

double Location::distance(Location &locat)

{

\x05double dis = 0.0

\x05dis = sqrt((this->x - locat.x)*(this->x - locat.x) + (this->y - locat.y)*(this->y - locat.y))

\x05return dis

}

double distance(Location &locat1,Location &locat2)

{

\x05double dis = 0.0

\x05dis = sqrt((locat1.x - locat2.x)*(locat1.x - locat2.x) + (locat1.y - locat2.y)*(locat1.y - locat2.y))

\x05return dis

}

int _tmain(int argc,_TCHAR* argv[])

{

\x05Location A(1.0,2.0)

\x05Location B(4.0,6.0)

\x05std::cout

两个错误

class Location{

public:

Location(int m,int n)

{X=mY=n

}

void Init(int initX,int initY)

{X=initXY=initY

}

int getX()

{return X

}

int getY()

{return Y

}

private:

int X,Y

}//类定义少了个分号

int main()

{

Location A3(3,2)//你的类的构造函数是带参的 所以你必须也要带参 这个是我随便改的

A3.Init(785,999)

cout<<A3.getX()<<" "<<A3.getY()<<endl

return 0

}

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