Django表单字段选择，添加属性

你必须对该字段进行子类化，以采取任何方式指定你想要的标题以及显示新属性的小部件。

如果你有这样的事情（请注意：完全未经测试）：

from django import formsfrom django.utils.html import escapefrom django.utils.encoding import force_unipreclass SelectWithTitles(forms.Select):    def __init__(self, *args, **kwargs):        super(SelectWithTitles, self).__init__(*args, **kwargs)        # Ensure the titles dict exists        self.titles = {}    def render_option(self, selected_choices, option_value, option_label):        title_html = (option_label in self.titles) and  u' title="%s" ' % escape(force_unipre(self.titles[option_label])) or ''        option_value = force_unipre(option_value)        selected_html = (option_value in selected_choices) and u' selected="selected"' or ''        return u'<option value="%s"%s%s>%s</option>' % ( escape(option_value), title_html, selected_html, conditional_escape(force_unipre(option_label)))class ChoiceFieldWithTitles(forms.ChoiceField):    widget = SelectWithTitles    def __init__(self, choices=(), *args, **kwargs):        choice_pairs = [(c[0], c[1]) for c in choices]        super(ChoiceFieldWithTitles, self).__init__(choices=choice_pairs, *args, **kwargs)        self.widget.titles = dict([(c[1], c[2]) for c in choices])

…你应该能够做到这一点：

PLANNING_CHOICES_WITH_TITLES = (    ('0', 'Every morning', 'bla1'),    ('1', 'Every night',   'bla2'),    ('2', 'Never',         'bla3'),)planning = forms.ChoiceFieldWithTitles(    required=True, choices=PLANNING_CHOICES_WITH_TITLES)