如何在Django中从urls.py访问HttpRequest

如何在Django中从urls.py访问HttpRequest

如果您真的想直接弄乱您的URLconf，可以这样做：

(r'^resources/$', lambda request: ListView.as_view(queryset=Resources.objects.filter(user=request.user.username), ...)(request))

或通过将视图子类化来访问请求：

class MyListView(ListView):    def dispatch(self, request, *args, **kwargs):        self.queryset = Resources.objects.filter(user = request.user.username)        return super(MyListView, self).dispatch(request, *args, **kwargs)