LeetCode 2028. 找出缺失的观测数据

2028. 找出缺失的观测数据

class Solution {
public:
    vector<int> missingRolls(vector<int>& rolls, int mean, int n) {
        vector<int> ans;
        int m = rolls.size();
        int t = mean * (m + n);
        for (auto i : rolls) t -= i;
        if (t < n || t > 6 * n) return ans;
        for (int i = 0; i < n; i++) ans.emplace_back(t / n);
        if (t / n * n < t)
        {
            int d = t - (t / n * n);
            for (int i = 0; d > 0; i++, d--) ans[i]++;
        }
        return ans;
    }
};