【C语言】实现扫雷游戏

【C语言】实现扫雷游戏 game.h(游戏实现函数的声明) 代码：

#pragma once

//头文件的包含
#include 
#include 
#include 

//符号的声明
#define ROW 9
#define COL 9

#define ROWS ROW+2
#define COLS COL+2

#define EASY_COUNT 10

//函数的声明

//初始化棋盘函数的声明
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);

//打印棋盘函数的声明
void DisplayBoard(char board[ROWS][COLS], int row, int col);

//布置雷函数的声明
void SetMine(char mine[ROWS][COLS], int row, int col);

//排雷函数的声明
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

game.c(游戏的实现逻辑) 代码：

#define _CRT_SECURE_NO_WARNINGS 1

#include "game.h"

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
	int i = 0;
	int j = 0;
	for (i = 0; i < rows; i++)
	{
		for (j = 0; j < cols; j++)
		{
			board[i][j] = set;
		}
	}
}

void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
	//1~9
	int i = 0;
	int j = 0;

	//列号的打印
	for (i = 0; i <= col; i++)
	{
		printf("%d ", i);
	}
	printf("n");
	for (i = 1; i <= row; i++)
	{
		printf("%d ", i);//打印行号

		for (j = 1; j <= col; j++)
		{
			printf("%c ", board[i][j]);
		}
		printf("n");
	}
}

//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col)
{
	int count = EASY_COUNT;

	while (count)
	{
		int x = rand() % row + 1;
		int y = rand() % col + 1;

		if (mine[x][y] == '0')
		{
			mine[x][y] = '1';
			count--;
		}
	}
}

static int get_mine_count(char mine[ROWS][COLS], int x, int y)
{
	return mine[x - 1][y]
		+ mine[x - 1][y - 1]
		+ mine[x][y - 1]
		+ mine[x + 1][y - 1]
		+ mine[x + 1][y]
		+ mine[x + 1][y + 1]
		+ mine[x][y + 1]
		+ mine[x - 1][y + 1]
		- 8 * '0';
}

//排雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	while (win < row * col - EASY_COUNT)
	{
		printf("请输入要排查的坐标:>");
		scanf("%d %d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (mine[x][y] == '1')
			{
				printf("很遗憾你被炸死了n");
				DisplayBoard(mine, row, col);
				break;
			}
			else
			{
				//计算x,y坐标周围有几个雷
				int n = get_mine_count(mine, x, y);
				show[x][y] = n + '0';
				DisplayBoard(show, row, col);
				win++;
			}
		}
		else
		{
			printf("输入坐标非法，请重新输入！n");
		}
	}
	if (win == row * col - EASY_COUNT)
	{
		printf("恭喜你，排雷成功！n");
		DisplayBoard(mine, row, col);
	}
}

test.c(游戏的测试逻辑) 代码：

#define _CRT_SECURE_NO_WARNINGS 1

#include "game.h"

void menu()
{
	printf("************************n");
	printf("******   1.play   ******n");
	printf("******   0.exit   ******n");
	printf("************************n");
}

void game()
{
	//printf("扫雷n");

	//创建数组
	char mine[ROWS][COLS] = { 0 };//存放布置好的雷的信息
	char show[ROWS][COLS] = { 0 };//存放排查出的雷的信息

	//初始化mine数组为全字符'0'
	InitBoard(mine, ROWS, COLS, '0');
	//初始化show数组为全字符'*'
	InitBoard(show, ROWS, COLS, '*');

	//打印棋盘
	//DisplayBoard(mine, ROW, COL);
	//DisplayBoard(show, ROW, COL);

	//布置雷
	SetMine(mine, ROW, COL);
	DisplayBoard(show, ROW, COL);

	//排雷
	FindMine(mine, show, ROW, COL);
}

void test()
{
	int input = 0;
	srand((unsigned int)time(NULL));
	do
	{
		menu();
		printf("请选择:>");
		scanf("%d", &input);
		switch (input)
		{
		case 1:
			//扫雷
			game();
			break;
		case 0:
			printf("退出游戏n");
			break;
		default:
			printf("选择错误n");
			break;
		}
	} while (input);
}

int main()
{
	test();
	return 0;
}

运行界面截图：